Consider the lines L_1: x - y = 1, L_2: x + y | vedclass

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(A) The slopes of the lines are as follows:$L_1: x - y = 1 \implies y = x - 1,$ slope $m_1 = 1.$$L_2: x + y = 1 \implies y = -x + 1,$ slope $m_2 = -1.

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$L_1 \perp L_2, L_2 \parallel L_3, L_1$ intersects $L_4.$

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(A) The slopes of the lines are as follows:$L_1: x - y = 1 \implies y = x - 1,$ slope $m_1 = 1.$$L_2: x + y = 1 \implies y = -x + 1,$ slope $m_2 = -1.$$L_3: 2x + 2y = 5 \implies y = -x + 2.5,$ slope $m_3 = -1.$$L_4: 2x - 2y = 7 \implies y = x - 3.5,$ slope $m_4 = 1.$Since $m_1 	imes m_2 = 1 	imes (-1) = -1,$ $L_1 \perp L_2.$Since $m_2 = m_3 = -1,$ $L_2 \parallel L_3.$Since $m_1 = m_4 = 1,$ $L_1 \parallel L_4.$Checking the options:Option $A$: $L_1 \perp L_2$ (True),$L_2 \parallel L_3$ (True),$L_1$ intersects $L_4$ (False,they are parallel).Option $B$: $L_1 \perp L_2$ (True),$L_1 \parallel L_3$ (False).Option $C$: $L_1 \perp L_2$ (True),$L_1 \parallel L_3$ (False).Option $D$: $L_1 \parallel L_4$ (True),$L_2 \parallel L_3$ (True),$L_2$ intersects $L_3$ (False,they are parallel).Wait,re-evaluating the options provided in the prompt. Given the standard form,$L_2 \parallel L_3$ is correct. Let's re-check the intersection logic. $L_2$ and $L_3$ are parallel,so they do not intersect. The question likely contains a typo in the options. Based on the slopes,$L_2 \parallel L_3$ and $L_1 \parallel L_4$ and $L_1 \perp L_2$ are the geometric properties.

Consider the lines $L_1: x - y = 1,$ $L_2: x + y = 1,$ $L_3: 2x + 2y = 5,$ and $L_4: 2x - 2y = 7.$ Which of the following statements is true?

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