The slope of a curve at any point is inversely proportional to twice the $y$-coordinate of that point. If the curve passes through $(4, 3)$,then the equation of the curve is:

  • A
    $x^2 = y + 5$
  • B
    $y^2 = x - 5$
  • C
    $y^2 = x + 5$
  • D
    $x^2 = y - 5$

Explore More

Similar Questions

The general solution of the differential equation $\frac{dy}{dx} = e^{x-y}$ is . . . . . . .

The general solution of the differential equation $x y(y+2) dy + (y^3-1) dx = 0$ is

The equation of the curve whose slope is $\frac{y - 1}{x^2 + x}$ and which passes through the point $(1, 0)$ is

Find the equation of the curve passing through the point $\left(0, \frac{\pi}{4}\right)$ whose differential equation is $\sin x \cos y \, dx + \cos x \sin y \, dy = 0$.

Find the general solution of the differential equation: $\frac{dy}{dx} + y = 1$ $(y \neq 1)$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo