What is the ratio of the velocity in the firs | vedclass

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(D) The velocity is given by the slope of the displacement-time graph.For the first $1 \ s$ ($t=0$ to $t=1$): $v_1 = \frac{\Delta x}{\Delta t} = \frac

Vedclass · Accepted Answer

$2:1$

Vedclass · Answer

(D) The velocity is given by the slope of the displacement-time graph.For the first $1 \ s$ ($t=0$ to $t=1$): $v_1 = \frac{\Delta x}{\Delta t} = \frac{30 - 0}{1 - 0} = 30 \ m/s$.For the next $2 \ s$ ($t=1$ to $t=3$): $v_2 = \frac{\Delta x}{\Delta t} = \frac{0 - 30}{3 - 1} = \frac{-30}{2} = -15 \ m/s$.The magnitude of velocity in the next $2 \ s$ is $|v_2| = 15 \ m/s$.The ratio of the velocity in the first $1 \ s$ to the magnitude of velocity in the next $2 \ s$ is $\frac{30}{15} = \frac{2}{1}$,which is $2:1$.

What is the ratio of the velocity in the first $1 \ s$ to the velocity in the next $2 \ s$ based on the given displacement-time graph?

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