Two bodies of masses 1 g and 9 g have equal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The relationship between momentum $P$,mass $m$,and kinetic energy $E$ is given by the formula $P = \sqrt{2mE}$.Since the kinetic energy $E$ is the

Vedclass · Accepted Answer

$1 : 3$

Vedclass · Answer

(C) The relationship between momentum $P$,mass $m$,and kinetic energy $E$ is given by the formula $P = \sqrt{2mE}$.Since the kinetic energy $E$ is the same for both bodies,we have $P \propto \sqrt{m}$.Therefore,the ratio of their momenta is $\frac{P_1}{P_2} = \sqrt{\frac{m_1}{m_2}}$.Given $m_1 = 1 \ g$ and $m_2 = 9 \ g$,we substitute these values:$\frac{P_1}{P_2} = \sqrt{\frac{1}{9}} = \frac{1}{3}$.Thus,the ratio of their momenta is $1 : 3$.

Two bodies of masses $1 \ g$ and $9 \ g$ have equal kinetic energy. The ratio of their momenta is:

Similar Questions

$A$ horizontal force of $5 \text{ N}$ is applied on a body of mass $5 \text{ kg}$, which is initially at rest on a frictionless table. What is the change in kinetic energy of the body after $10 \text{ s}$?

If the velocity of an object of mass $300 \ g$ is $(3\hat{i} + 4\hat{j}) \ m/s$,then its kinetic energy is . . . . . . $J$.

Express momentum in terms of mass and kinetic energy.

Two bodies with kinetic energies in the ratio of $4 : 1$ are moving with equal linear momentum. The ratio of their masses is

The kinetic energy acquired by a mass $m$ in travelling a certain distance $d$ starting from rest under the action of a constant force is directly proportional to

Vedclass Test Series

Exam Paper Generator

Online Exam Module