(C) Given: Mass $m = 300 \ g = 0.3 \ kg$.Velocity vector $\vec{v} = (3\hat{i} + 4\hat{j}) \ m/s$.The magnitude of velocity is $v = |\vec{v}| = \sqrt{3

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(C) Given: Mass $m = 300 \ g = 0.3 \ kg$.Velocity vector $\vec{v} = (3\hat{i} + 4\hat{j}) \ m/s$.The magnitude of velocity is $v = |\vec{v}| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \ m/s$.The formula for kinetic energy is $K = \frac{1}{2}mv^2$.Substituting the values: $K = \frac{1}{2} \times 0.3 \times (5)^2$.$K = 0.15 \times 25 = 3.75 \ J$.

Class 11 Physics Work, Energy, Power and Collision Kinetic Energy

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If the velocity of an object of mass $300 \ g$ is $(3\hat{i} + 4\hat{j}) \ m/s$,then its kinetic energy is . . . . . . $J$.

A
$1.35$
B
$2.4$
C
$3.75$
D
$7.35$

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If the velocity of an object of mass $300 \ g$ is $(3\hat{i} + 4\hat{j}) \ m/s$,then its kinetic energy is . . . . . . $J$.

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