If a body takes time t to reach the ground wh | vedclass

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(C) The time taken for a body to fall from a height $h$ under gravity is given by the kinematic equation $h = \frac{1}{2}gt^2$,which simplifies to $t

Vedclass · Accepted Answer

$\sqrt{6}t$

Vedclass · Answer

(C) The time taken for a body to fall from a height $h$ under gravity is given by the kinematic equation $h = \frac{1}{2}gt^2$,which simplifies to $t = \sqrt{\frac{2h}{g}}$.For Earth,$t_{earth} = \sqrt{\frac{2h}{g_{earth}}}$.For the Moon,$t_{moon} = \sqrt{\frac{2h}{g_{moon}}}$.Given that the acceleration due to gravity on the Moon is $g_{moon} = \frac{g_{earth}}{6}$,we can write the ratio as:$\frac{t_{moon}}{t_{earth}} = \sqrt{\frac{g_{earth}}{g_{moon}}} = \sqrt{\frac{g_{earth}}{g_{earth}/6}} = \sqrt{6}$.Therefore,$t_{moon} = \sqrt{6}t$.

If a body takes time $t$ to reach the ground when dropped from a height $h$ on Earth,how much time will it take to reach the ground when dropped from the same height $h$ on the Moon?

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