For the given system,the angle theta will be | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the tension in the string be $T$. Since the same string passes over the pulleys,the tension $T$ is uniform throughout the string.Therefore,$T_

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(B) Let the tension in the string be $T$. Since the same string passes over the pulleys,the tension $T$ is uniform throughout the string.Therefore,$T_1 = T_2 = T = W$ (as the weight $W$ is hanging from the pulley $P_1$ and the other end is also supporting weight $W$).For the equilibrium of pulley $P_1$ in the horizontal direction:$T_1 \cos 	heta = T_2 \cos 	heta$This is satisfied as $T_1 = T_2 = W$.For the equilibrium of pulley $P_1$ in the vertical direction:$T_1 \sin 	heta + T_2 \sin 	heta = W$Since $T_1 = T_2 = W$,we have:$W \sin 	heta + W \sin 	heta = W$$2W \sin 	heta = W$$\sin 	heta = \frac{1}{2}$$	heta = 30^\circ$

For the given system,the angle $\theta$ will be ......... $^o$.

Similar Questions

In the figure shown,both blocks are released from rest. Find the time taken for them to cross each other. (Assume $g = 10 \ m/s^2$)

If $m_1 = 4m_2$,and the acceleration of $m_1$ is $a$,then find $a$.

Tension in the rope at the rigid support is ............ $N$ $\left(g=10 \,m / s ^2\right)$

The system of two masses $2 \ kg$ and $3 \ kg$ as shown in the figure is released from rest. The work done on the $3 \ kg$ block by the force of gravity during the first $2 \ s$ of its motion is $\left(g=10 \ m/s^2\right)$. (in $J$)

$A$ monkey of mass $20\,kg$ is holding a vertical rope. The rope can break when a mass of $25\,kg$ is suspended from it. What is the maximum acceleration with which the monkey can climb up along the rope (in $,m/s^2$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module