A simple pendulum keeps correct time at 0^{ci | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The time lost by a pendulum clock due to a change in temperature is given by the formula: $\Delta t = \frac{1}{2} \alpha \Delta 	heta T$,where $\

Vedclass · Accepted Answer

$\frac{1}{86400} \, /^{\circ}C$

Vedclass · Answer

(A) The time lost by a pendulum clock due to a change in temperature is given by the formula: $\Delta t = \frac{1}{2} \alpha \Delta 	heta T$,where $\Delta t$ is the time lost,$\alpha$ is the coefficient of linear expansion,$\Delta 	heta$ is the change in temperature,and $T$ is the total time in a day $(86400 \, s)$.Given: $\Delta t = 12.5 \, s$,$\Delta 	heta = 25^{\circ}C - 0^{\circ}C = 25^{\circ}C$,and $T = 86400 \, s$.Substituting the values: $12.5 = \frac{1}{2} 	imes \alpha 	imes 25 	imes 86400$.$12.5 = \alpha 	imes 1080000$.$\alpha = \frac{12.5}{1080000} = \frac{12.5}{12.5 	imes 86400} = \frac{1}{86400} \, /^{\circ}C$.

$A$ simple pendulum keeps correct time at $0^{\circ}C$. At $25^{\circ}C$,it loses $12.5 \, s$ in a day. What is the coefficient of linear expansion of the metal of the pendulum?

Similar Questions

If the speed $v$ of the bob in a simple pendulum is plotted against the tangential acceleration $a$,the correct graph will be represented by

The length of a simple pendulum is increased by $1\%$. Its time period will

If a simple pendulum is released from the given position,find the velocity of the bob when it reaches the lowest position. (Take $g = 10 \ m/s^2$) (in $m/s$)

The bob of a simple pendulum of length $200 \ cm$ is released from a horizontal position. If $10 \%$ of its initial energy is lost due to air resistance,then the speed of the bob at the mean position is (Acceleration due to gravity $= 10 \ m \ s^{-2}$) (in $m \ s^{-1}$)

$A$ hollow sphere is filled with water through a small hole in it. It is then hung by a long thread and made to oscillate. As the water slowly flows out of the hole at the bottom, the period of oscillation will

Vedclass Test Series

Exam Paper Generator

Online Exam Module