What is the maximum velocity of a simple harm | vedclass

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Question

(C) The maximum velocity $(v_{\max})$ of a particle in simple harmonic motion is given by the formula: $v_{\max} = a\omega$ where $a$ is the amplitude

Vedclass · Accepted Answer

$2\pi \ m/s$

Vedclass · Answer

(C) The maximum velocity $(v_{\max})$ of a particle in simple harmonic motion is given by the formula: $v_{\max} = a\omega$ where $a$ is the amplitude and $\omega$ is the angular frequency. Given: Amplitude $a = 2 \ m$ Time period $T = 2 \ s$ We know that $\omega = \frac{2\pi}{T}$. Substituting the values: $\omega = \frac{2\pi}{2} = \pi \ rad/s$ Now,calculating $v_{\max}$: $v_{\max} = 2 	imes \pi = 2\pi \ m/s$ Therefore,the correct option is $C$.

What is the maximum velocity of a simple harmonic motion with an amplitude of $2 \ m$ and a time period of $2 \ s$?

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