What is the maximum velocity of a simple harm | vedclass

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(B) The maximum velocity $(v_{\max})$ of a particle executing simple harmonic motion is given by the formula: $v_{\max} = a\omega$,where $a$ is the am

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$\pi \ cm/s$

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(B) The maximum velocity $(v_{\max})$ of a particle executing simple harmonic motion is given by the formula: $v_{\max} = a\omega$,where $a$ is the amplitude and $\omega$ is the angular frequency.Given: Amplitude $a = 3 \ cm$,Time period $T = 6 \ s$.The angular frequency is $\omega = \frac{2\pi}{T} = \frac{2\pi}{6} = \frac{\pi}{3} \ rad/s$.Substituting these values into the formula:$v_{\max} = 3 	imes \frac{\pi}{3} = \pi \ cm/s$.Therefore,the maximum velocity is $\pi \ cm/s$.

What is the maximum velocity of a simple harmonic motion with an amplitude of $3 \ cm$ and a time period of $6 \ s$?

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