$A$ particle of mass $10 \, g$ performs simple harmonic motion with an amplitude of $0.5 \, m$ and an angular frequency of $10 \, rad/s$. What is the maximum force acting on it in $N$?

The variation of displacement with time of a simple harmonic motion $(SHM)$ for a particle of mass $m$ is represented by $y = 2 \sin \left(\frac{\pi t}{2} + \phi\right) \text{ cm}$. The maximum acceleration of the particle is

The amplitude of a particle executing $SHM$ is $2 \, cm$ and the force acting at the extreme position on the particle is $4 \, N$. What is the force at the midway point between the mean position and the extreme point (in $, N$)?

The graphs in the figure show that a quantity $y$ varies with displacement $d$ in a system undergoing simple harmonic motion. Which graph best represents the relationship obtained when $y$ is the unbalanced force acting on the system?

For a particle performing $S.H.M.$, the displacement-time graph is shown. For that particle, the force-time graph is correctly represented by which of the following?

The acceleration-displacement graph of a particle executing $SHM$ is shown in the figure. The time period of the simple harmonic motion is: