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(B) According to the quantization of charge,the total charge $Q$ is given by $Q = ne$,where $n$ is the number of electrons and $e$ is the elementary c

Vedclass · Accepted Answer

$6.25 	imes 10^{18}$

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(B) According to the quantization of charge,the total charge $Q$ is given by $Q = ne$,where $n$ is the number of electrons and $e$ is the elementary charge.Given $Q = 1 \ C$ and $e = 1.6 	imes 10^{-19} \ C$.Rearranging the formula for $n$: $n = \frac{Q}{e}$.Substituting the values: $n = \frac{1}{1.6 	imes 10^{-19}} = \frac{10^{19}}{1.6} = 0.625 	imes 10^{19} = 6.25 	imes 10^{18}$.Therefore,the number of electrons in $1 \ C$ of charge is $6.25 	imes 10^{18}$.

The number of electrons in $1 \ C$ of charge is:

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