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(B) The formula for drift velocity is given by $v_d = \frac{I}{neA}$.Given:$I = 24 \, mA = 24 	imes 10^{-3} \, A$$n = 3 	imes 10^{23} \, m^{-3}$$e =

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$5 	imes 10^{-3} \, m/s$

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(B) The formula for drift velocity is given by $v_d = \frac{I}{neA}$.Given:$I = 24 \, mA = 24 	imes 10^{-3} \, A$$n = 3 	imes 10^{23} \, m^{-3}$$e = 1.6 	imes 10^{-19} \, C$$A = 1 \, cm^2 = 10^{-4} \, m^2$Substituting these values into the formula:$v_d = \frac{24 	imes 10^{-3}}{3 	imes 10^{23} 	imes 1.6 	imes 10^{-19} 	imes 10^{-4}}$$v_d = \frac{24 	imes 10^{-3}}{4.8 	imes 10^{0}}$$v_d = 5 	imes 10^{-3} \, m/s$.

In a wire with a cross-sectional area of $1 \, cm^2$ carrying a current of $24 \, mA$,the electron number density is $3 \times 10^{23} \, m^{-3}$. What is the drift velocity?

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