For the given circuit,if i = 0.25 , A,what is | vedclass

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(D) Given: Current $i = 0.25 \, A$ and Voltage $V = 12 \, V$.The equivalent resistance of the circuit is given by Ohm's law: $R_{eq} = \frac{V}{i} = \

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$42$

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(D) Given: Current $i = 0.25 \, A$ and Voltage $V = 12 \, V$.The equivalent resistance of the circuit is given by Ohm's law: $R_{eq} = \frac{V}{i} = \frac{12}{0.25} = 48 \, \Omega$.From the circuit diagram,the resistor $R$ is in series with the parallel combination of $60 \, \Omega$,$20 \, \Omega$,and $10 \, \Omega$ resistors.The equivalent resistance of the parallel part is $\frac{1}{R_p} = \frac{1}{60} + \frac{1}{20} + \frac{1}{10} = \frac{1 + 3 + 6}{60} = \frac{10}{60} = \frac{1}{6}$.Thus,$R_p = 6 \, \Omega$.The total equivalent resistance is $R_{eq} = R + R_p = R + 6$.Equating the two expressions for $R_{eq}$: $R + 6 = 48$.Therefore,$R = 48 - 6 = 42 \, \Omega$.

For the given circuit,if $i = 0.25 \, A$,what is the value of $R$ in $\Omega$?

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