Two identical bulbs,each rated 500 , W and 22 | vedclass

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(A) The resistance $R$ of each bulb is given by $R = \frac{V^2}{P} = \frac{220^2}{500} \, \Omega$.When two identical bulbs are connected in series to

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$\frac{125}{4} \, W$

Vedclass · Answer

(A) The resistance $R$ of each bulb is given by $R = \frac{V^2}{P} = \frac{220^2}{500} \, \Omega$.When two identical bulbs are connected in series to a $110 \, V$ supply,the voltage across each bulb is $V' = \frac{110}{2} = 55 \, V$.The power consumed by each bulb is $P' = \frac{(V')^2}{R} = \frac{V'^2}{(V^2/P)} = P 	imes \left( \frac{V'}{V} ight)^2$.Substituting the values: $P' = 500 	imes \left( \frac{55}{220} ight)^2 = 500 	imes \left( \frac{1}{4} ight)^2 = 500 	imes \frac{1}{16} = \frac{125}{4} \, W$.

Two identical bulbs,each rated $500 \, W$ and $220 \, V$,are connected in series to a $110 \, V$ supply. What is the power consumed by each bulb?

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