$A$ magnetic rod of length $L$ has a magnetic dipole moment $M$. If it is bent into a semicircle,what will be its new magnetic dipole moment?

$A$ thin rod of length $L$ is magnetized and has a magnetic moment $M$. The rod is then bent into a semicircular arc. The magnetic moment in the new shape is

$A$ bar magnet $AB$ is cut into two equal parts as shown in the figure. One part is kept over the other so that the pole $C_{2}$ is above $C_{1}$. If $M$ is the magnetic moment of the original magnet,the magnetic moment of the combination so formed is

$A$ bar magnet having pole strength $q_m$ and magnetic moment $m$ is divided into two equal parts along its length. The new pole strength is . . . . . . and the magnetic moment is . . . . . . respectively.

What does the analogy of a bar magnet's and a solenoid's magnetic field lines suggest?

$A$ bar magnet having centre $O$ has a length of $4 \ cm$. Point $P_1$ is in the broad side-on (equatorial) position and $P_2$ is in the end side-on (axial) position with $OP_1 = OP_2 = 10 \ m$. The ratio of magnetic intensities $H$ at $P_1$ and $P_2$ is: