A bar magnet AB is cut into two equal parts a | vedclass

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(C) The magnetic moment of a bar magnet is given by $M = m 	imes 2l$,where $m$ is the pole strength and $2l$ is the length of the magnet.When the mag

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(C) The magnetic moment of a bar magnet is given by $M = m 	imes 2l$,where $m$ is the pole strength and $2l$ is the length of the magnet.When the magnet is cut into two equal parts perpendicular to its length,the length of each part becomes $l$ and the pole strength remains $m$.Thus,the magnetic moment of each part is $M' = m 	imes l = \frac{M}{2}$.Let the original magnet have poles $A$ (say North) and $B$ (South). After cutting,the first part has poles $A$ and $C_1$,and the second part has poles $C_2$ and $B$.When the second part is placed over the first such that $C_2$ is above $C_1$,the poles $C_1$ and $C_2$ will have opposite polarities. If $C_1$ is South,then $C_2$ will be North.In this configuration,the magnetic moments of the two parts are in opposite directions.The net magnetic moment of the combination is $M_{net} = M' - M' = 0$.

$A$ bar magnet $AB$ is cut into two equal parts as shown in the figure. One part is kept over the other so that the pole $C_{2}$ is above $C_{1}$. If $M$ is the magnetic moment of the original magnet,the magnetic moment of the combination so formed is

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