The length of a steel wire is L and its magne | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The initial magnetic moment is given by $M = m 	imes L$,where $m$ is the pole strength and $L$ is the length of the wire.When the wire is bent in

Vedclass · Accepted Answer

$2M/\pi$

Vedclass · Answer

(B) The initial magnetic moment is given by $M = m 	imes L$,where $m$ is the pole strength and $L$ is the length of the wire.When the wire is bent into a semicircle,the length $L$ becomes the arc length of the semicircle,so $L = \pi R$,where $R$ is the radius of the semicircle.Thus,$R = L / \pi$.The effective length (distance between the two poles) of the semicircle is the diameter,which is $2R$.The new magnetic moment $M_{	ext{new}}$ is given by $M_{	ext{new}} = m 	imes (2R)$.Substituting $R = L / \pi$,we get $M_{	ext{new}} = m 	imes 2 	imes (L / \pi) = (2 / \pi) 	imes (m 	imes L)$.Since $M = m 	imes L$,the new magnetic moment is $M_{	ext{new}} = 2M / \pi$.

The length of a steel wire is $L$ and its magnetic moment is $M$. On bending it into the shape of a semicircle,its magnetic moment will be

Similar Questions

$A$ magnetic rod of length $L$ has a magnetic dipole moment $M$. If it is bent into a semicircle,what will be its new magnetic dipole moment?

What happens when a small bar magnet is kept on a glass plate and iron filings are sprinkled on it?

Two lines of force due to a bar magnet:

$A$ steel wire of length $l$ and magnetic moment $M$ is bent into a semicircular arc of radius $R$. The new magnetic moment is

The magnetic field lines due to a bar magnet are correctly shown in

Vedclass Test Series

Exam Paper Generator

Online Exam Module