The loops have lengths $L$ or $2L$. All loops enter a magnetic field $\vec{B}$ with the same velocity $v$. Which of the following is correct?

There is a uniform magnetic field $B$ normal to the $xy$ plane. $A$ conductor $ABC$ has length $AB = l_1$,parallel to the $x$-axis,and length $BC = l_2$,parallel to the $y$-axis. $ABC$ moves in the $xy$ plane with velocity $\vec{v} = v_x \hat{i} + v_y \hat{j}$. The potential difference between $A$ and $C$ is proportional to

$A$ rectangular wire loop of sides $8 \;cm$ and $2 \;cm$ with a small cut is moving out of a region of uniform magnetic field of magnitude $0.3 \;T$ directed normal to the loop. What is the emf developed across the cut if the velocity of the loop is $1 \;cm \,s^{-1}$ in a direction normal to the $(a)$ longer side,$(b)$ shorter side of the loop? For how long does the induced voltage last in each case?

$A$ conducting rod $PQ$ of length $l = 5 \ m$ is oriented as shown in the figure. It is moving with a velocity $\vec{V} = (2 \ m/s) \hat{i}$ without any rotation in a uniform magnetic field $\vec{B} = (3 \hat{j} + 4 \hat{k}) \ T$. The induced $Emf$ in the rod is...........$V$.

$A$ conducting rod of mass $m$ and length $l$ is free to move without friction on two parallel long conducting rails,as shown in the figure. There is a resistance $R$ across the rails. In the entire space,there is a uniform magnetic field $B$ normal to the plane of the rod and rails. The rod is given an impulsive velocity $v_0$. What happens to the initial kinetic energy $\frac{1}{2} m v_0^2$?

Initially,a rectangular coil with its length vertical is moving out with a constant velocity $v$ in a constant magnetic field $B$ towards the right. Now,the same coil is rotated through $90^{\circ}$ in the same plane in the same magnetic field $B$,and the coil is moving with the same velocity $v$. The magnitude of the induced e.m.f. is now