A conducting rod of mass m and length l is fr | vedclass

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(A) When the conducting rod moves with velocity $v$ in a uniform magnetic field $B$,a motional $emf$ $\varepsilon = Blv$ is induced across the rod.Thi

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It will be converted fully into heat energy in the resistor.

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(A) When the conducting rod moves with velocity $v$ in a uniform magnetic field $B$,a motional $emf$ $\varepsilon = Blv$ is induced across the rod.This $emf$ drives an induced current $I = \frac{\varepsilon}{R} = \frac{Blv}{R}$ through the circuit.The current-carrying rod in the magnetic field experiences a magnetic force $F_m = IlB = \frac{B^2l^2v}{R}$ acting in the direction opposite to the velocity $v$.This force causes the rod to decelerate. As the rod moves,the kinetic energy is dissipated as heat in the resistor due to the Joule heating effect $(P = I^2R)$.Since there is no other external force or energy storage mechanism (like a capacitor or inductor),the entire initial kinetic energy $\frac{1}{2} m v_0^2$ will eventually be dissipated as heat in the resistor $R$ as the rod comes to rest.

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