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(C) $1$. The angle of the mirror with the horizontal is $30^\circ$. $2$. The incident ray is vertical,so it makes an angle of $90^\circ - 30^\circ = 6

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$60$

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(C) $1$. The angle of the mirror with the horizontal is $30^\circ$. $2$. The incident ray is vertical,so it makes an angle of $90^\circ - 30^\circ = 60^\circ$ with the mirror surface. $3$. According to the law of reflection,the angle of incidence $(i)$ equals the angle of reflection $(r)$. $4$. The angle of incidence $i$ is the angle between the incident ray and the normal. Since the ray makes $60^\circ$ with the mirror,$i = 90^\circ - 60^\circ = 30^\circ$. $5$. Thus,the angle of reflection $r = 30^\circ$. $6$. The angle between the reflected ray and the mirror surface is $90^\circ - r = 90^\circ - 30^\circ = 60^\circ$.

$A$ plane mirror makes an angle of $30^\circ$ with the horizontal. $A$ vertical ray is incident on the mirror. What is the angle between the mirror and the reflected ray in degrees?

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