For a prism with refractive index $\mu = 1.5$,the angle of minimum deviation is equal to the angle of incidence. Find the prism angle $A$ in degrees. (Given: $\cos 41^o = 0.75$)

For a prism of apex angle $45^o$,it is found that the angle of emergence is $45^o$ for grazing incidence. Calculate the refractive index of the prism.

$A$ prism is made up of material of refractive index $\sqrt{3}$. The angle of the prism is $A$. If the angle of minimum deviation is equal to the angle of the prism,then the value of $A$ is: (in $^{\circ}$)

$A$ ray of light is incident at an angle '$i$' on one face of a thin angled prism. The ray emerges normally from the other face. If the refractive index of the glass prism is '$n$' and the angle of the prism is '$A$',then the value of '$i$' is:

$A$ ray of light is incident on one face of an equilateral glass prism having refractive index $\sqrt{2}$. It produces the emergent ray which just grazes along the adjacent face. The value of angle of incidence is

Consider two equivalent,triangular hollow prisms $A$ and $B$ made of thin glass plates and arranged with negligible spacing as shown in the figure. $A$ beam of white light is incident on prism $A$ from the left. Given that the refractive index of water is inversely related to temperature,the beam to the right of prism $B$ would not appear white,if