$A$ compound with formula $C_4H_{10}O$ on oxidation gives $C_4H_8O$,which forms an oxime and gives a positive iodoform test. The original compound on reaction with concentrated $H_2SO_4$ gives $C_4H_8$. What is the structure of the compound?
- A$CH_3CH_2CH_2CH_2OH$
- B$CH_3CH(OH)CH_2CH_3$
- C$(CH_3)_3COH$
- D$CH_3CH_2-O-CH_2CH_3$
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