What will be the major product?

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(C) The given reactant is a tetra-aldehyde compound,specifically $2,2',6,6'$-tetrabenzenedicarbaldehyde. When treated with concentrated $NaOH$

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(C) The given reactant is a tetra-aldehyde compound,specifically $2,2',6,6'$-tetrabenzenedicarbaldehyde. When treated with concentrated $NaOH$ at $100^{\circ}C$,it undergoes an intramolecular Cannizzaro reaction. In the Cannizzaro reaction,aldehydes lacking $\alpha$-hydrogen atoms undergo self-oxidation and reduction in the presence of a strong base. Here,the aldehyde groups are reduced to primary alcohol groups $(-CH_2OH)$ and oxidized to carboxylate groups $(-COO^-)$,which upon acidification with $H^+/H_2O$ yield carboxylic acid groups $(-COOH)$. The final product is a compound containing both alcohol and carboxylic acid functional groups,as shown in option $C$.

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