When propionamide is treated with Br_2 and Na | vedclass

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(D) This reaction is known as the Hofmann bromamide degradation reaction.In this reaction,an amide is converted into a primary amine with one carbon a

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Ethyl amine

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(D) This reaction is known as the Hofmann bromamide degradation reaction.In this reaction,an amide is converted into a primary amine with one carbon atom less than the original amide.$CH_3CH_2CONH_2 + Br_2 + 4NaOH \rightarrow CH_3CH_2NH_2 + 2NaBr + Na_2CO_3 + 2H_2O$Propionamide $(CH_3CH_2CONH_2)$ reacts to form ethyl amine $(CH_3CH_2NH_2)$.

When propionamide is treated with $Br_2$ and $NaOH$,which of the following products is obtained?

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