g_e and g_p denote the acceleration due to gr | vedclass

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(B) The acceleration due to gravity on the surface of a planet is given by the formula $g = \frac{GM}{R^2}$,where $G$ is the universal gravitational c

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$g_p = g_e / 2$

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(B) The acceleration due to gravity on the surface of a planet is given by the formula $g = \frac{GM}{R^2}$,where $G$ is the universal gravitational constant,$M$ is the mass of the planet,and $R$ is its radius.For Earth,$g_e = \frac{GM_e}{R_e^2}$.For the other planet,the mass $M_p = 2M_e$ and the radius $R_p = 2R_e$.Substituting these values into the formula for $g_p$:$g_p = \frac{G(2M_e)}{(2R_e)^2} = \frac{2GM_e}{4R_e^2} = \frac{1}{2} \left( \frac{GM_e}{R_e^2} \right)$.Since $g_e = \frac{GM_e}{R_e^2}$,we get $g_p = \frac{g_e}{2}$.

$g_e$ and $g_p$ denote the acceleration due to gravity on the surface of the Earth and another planet whose mass and radius are twice that of the Earth. Then:

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