If A = {(x, y) : x^2 + y^2 = 25} and B = {(x, | vedclass

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(D) The set $A$ represents a circle with center $(0, 0)$ and radius $r = 5$,given by $x^2 + y^2 = 5^2$.The set $B$ represents an ellipse given by $x^2

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(D) The set $A$ represents a circle with center $(0, 0)$ and radius $r = 5$,given by $x^2 + y^2 = 5^2$.The set $B$ represents an ellipse given by $x^2 + 9y^2 = 144$,which can be written as $\frac{x^2}{144} + \frac{y^2}{16} = 1$,or $\frac{x^2}{12^2} + \frac{y^2}{4^2} = 1$.Comparing the two,the circle has a radius of $5$. The ellipse has semi-major axis $a = 12$ along the $x$-axis and semi-minor axis $b = 4$ along the $y$-axis.Since the circle's radius $(5)$ is greater than the ellipse's semi-minor axis $(4)$ but less than its semi-major axis $(12)$,the circle intersects the ellipse at four distinct points.

If $A = \{(x, y) : x^2 + y^2 = 25\}$ and $B = \{(x, y) : x^2 + 9y^2 = 144\}$,then the number of points in $A \cap B$ is

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