Let A and B be two sets,then: | vedclass

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(B) For any two sets $A$ and $B$,the intersection $A \cap B$ contains elements common to both $A$ and $B$. Thus,$A \cap B \subseteq A$ and $A \cap B \

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$A \cap B \subseteq A \cup B$

Vedclass · Answer

(B) For any two sets $A$ and $B$,the intersection $A \cap B$ contains elements common to both $A$ and $B$. Thus,$A \cap B \subseteq A$ and $A \cap B \subseteq B$. Similarly,the union $A \cup B$ contains all elements that are in $A$ or in $B$. Thus,$A \subseteq A \cup B$ and $B \subseteq A \cup B$. Since every element of $A \cap B$ is also an element of $A$ (or $B$),and every element of $A$ (or $B$) is an element of $A \cup B$,it follows that $A \cap B \subseteq A \cup B$.

Let $A$ and $B$ be two sets,then:

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