If A and B are two sets,then A times B = B ti | vedclass

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(C) The Cartesian product of two sets $A$ and $B$ is defined as $A 	imes B = \{(a, b) : a \in A, b \in B\}$.For $A 	imes B = B 	imes A$,every eleme

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$A = B$

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(C) The Cartesian product of two sets $A$ and $B$ is defined as $A 	imes B = \{(a, b) : a \in A, b \in B\}$.For $A 	imes B = B 	imes A$,every element $(a, b)$ in $A 	imes B$ must be equal to an element $(b, a)$ in $B 	imes A$.If $A$ and $B$ are non-empty sets,then $A 	imes B = B 	imes A$ implies $A = B$.If either $A$ or $B$ is an empty set (i.e.,$\phi$),then $A 	imes B = \phi$ and $B 	imes A = \phi$,so $A 	imes B = B 	imes A$ holds even if $A 
eq B$.However,in the context of standard set theory problems of this type,the condition $A = B$ is the primary requirement for non-empty sets to satisfy the equality.

If $A$ and $B$ are two sets,then $A \times B = B \times A$ if and only if

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