Let $A = \{1, 2, 3, 4, 5\}$ and $B = \{2, 3, 6, 7\}$. Then the number of elements in $(A \times B) \cap (B \times A)$ is:

  • A
    $18$
  • B
    $6$
  • C
    $4$
  • D
    $0$

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