If $\frac{x}{(x - 1)(x^2 + 1)^2} = \frac{1}{4}\left[ \frac{1}{(x - 1)} - \frac{x + 1}{x^2 + 1} \right] + y$,then $y =$

  • A
    $\frac{1 - x}{2(x^2 + 1)^2}$
  • B
    $\frac{1 - x}{3(x^2 + 1)}$
  • C
    $\frac{1 + x}{2(x^2 - 1)^2}$
  • D
    None of these

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