(A) The potential difference $V$ across a battery is given by the equation $V = E - ir$.Comparing this with the equation of a straight line $y = mx +

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Internal resistance of the battery is $5\,\Omega$.

(A) The potential difference $V$ across a battery is given by the equation $V = E - ir$.Comparing this with the equation of a straight line $y = mx + c$,we get $V = -ri + E$.From the given graph,the intercept on the $V$-axis is $E = 10\,V$.The intercept on the $i$-axis is the short-circuit current when $V = 0$,which is $i_{max} = E/r = 2\,A$.Substituting $E = 10\,V$ and $i_{max} = 2\,A$,we get $r = E / i_{max} = 10 / 2 = 5\,\Omega$.Thus,the internal resistance $r = 5\,\Omega$,the $emf$ $E = 10\,V$,and the maximum current is $2\,A$.Comparing these with the options,option $A$ is correct.

Class 12 Physics Current Electricity Mix Examples-Current Electricity

Medium

$A$ battery of $emf$ $E$ and internal resistance $r$ is connected across a resistance $R$. Resistance $R$ can be adjusted to any value greater than or equal to zero. $A$ graph is plotted between the current $(i)$ passing through the resistance and potential difference $(V)$ across it. Select the correct alternative$(s)$.

A
Internal resistance of the battery is $5\,\Omega$.
B
Emf of the battery is $20\,V$.
C
Maximum current which can be taken from the battery is $2\,A$.
D
$V-i$ graph can never be a straight line as shown in figure.

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Mix Examples-Current Electricity

Four lamps are connected as shown in the figure. When switch $S_2$ is open and switch $S_1$ is at position $2$,lamp $b$ is the brightest,and lamps $c$ and $d$ are the dimmest and have the same brightness. Now,if $S_2$ is closed and $S_1$ is at position $1$,what is the sequence of brightness of the lamps (starting from the brightest)?

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When a current passes through a wire whose different parts are maintained at different temperatures,the evolution or absorption of heat all along the length of the wire is known as:

Medium

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If in the circuit shown below,the internal resistance of the battery is $1.5 \, \Omega$ and $V_P$ and $V_Q$ are the potentials at $P$ and $Q$ respectively,what is the potential difference between the points $P$ and $Q$?

Difficult

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For the circuit shown in the figure:
$(A)$ The current $I$ through the battery is $7.5 \text{ mA}$.
$(B)$ The potential difference across $R_L$ is $18 \text{ V}$.
$(C)$ The ratio of powers dissipated in $R_1$ and $R_2$ is $3$.
$(D)$ If $R_1$ and $R_2$ are interchanged,the magnitude of the power dissipated in $R_L$ will decrease by a factor of $9$.

DifficultIIT 2009

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$A$ fuse wire with radius $1\, mm$ blows at $1.5\, A$. The radius of the fuse wire of the same material to blow at $3\, A$ will be:

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When a current passes through a wire whose different parts are maintained at different temperatures,the evolution or absorption of heat all along the length of the wire is known as:

If in the circuit shown below,the internal resistance of the battery is $1.5 \, \Omega$ and $V_P$ and $V_Q$ are the potentials at $P$ and $Q$ respectively,what is the potential difference between the points $P$ and $Q$?

$A$ fuse wire with radius $1\, mm$ blows at $1.5\, A$. The radius of the fuse wire of the same material to blow at $3\, A$ will be:

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