AB and CD are smooth parallel rails,separated | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic force on the conductor $EF$ is given by $\vec{F}_{mag} = i(\vec{l} 	imes \vec{B})$.Since the magnetic field $\vec{B}$ is directed ve

Vedclass · Accepted Answer

Both $(A)$ and $(B)$

Vedclass · Answer

(D) The magnetic force on the conductor $EF$ is given by $\vec{F}_{mag} = i(\vec{l} 	imes \vec{B})$.Since the magnetic field $\vec{B}$ is directed vertically upwards and the conductor $EF$ is on an incline,the angle between the length vector $\vec{l}$ (along $EF$) and the magnetic field $\vec{B}$ is $(90^\circ - 	heta)$.The magnitude of the magnetic force is $F_{mag} = i l B \sin(90^\circ - 	heta) = i l B \cos 	heta$.Using the right-hand rule,for the magnetic force to act up the inclined plane,the current $i$ must flow from $E$ to $F$.The component of the gravitational force acting down the inclined plane is $mg \sin 	heta$.For the conductor to be in equilibrium,the magnetic force must balance the component of the weight along the incline:$i l B \cos 	heta = mg \sin 	heta$Dividing both sides by $\cos 	heta$,we get:$i l B = mg 	an 	heta$.Thus,both conditions $(A)$ and $(B)$ are required for equilibrium.

Similar Questions

Two very long straight parallel conductors of negligible cross-section carrying equal electric current of $1 \text{ mA}$ are placed one metre apart in a vacuum. The force produced per metre length is $\qquad \text{ N}$. (Given: $\mu_0 = 4\pi \times 10^{-7} \text{ T m A}^{-1}$)

The resultant force on the current loop $PQRS$ due to a long current-carrying conductor will be $..... \times 10^{-4} \text{ N}$.

$A$ current of $3\, A$ is flowing in a linear conductor of length $40\, cm$. The conductor is placed in a magnetic field of strength $500\, G$ and makes an angle of $30^\circ$ with the direction of the field. The magnitude of the force experienced by the conductor is:

$A$ current of $1 \ A$ is flowing along the positive $x$-axis through a straight wire of length $0.5 \ m$ placed in a region of a magnetic field given by $\vec{B} = (2\hat{i} + 4\hat{j}) \ T$. The magnitude and the direction of the force experienced by the wire are, respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module