A block of mass m moving with a velocity v_0 | vedclass

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(C) Observer $B$ is standing on the block,which means observer $B$ is in a non-inertial frame of reference.In the frame of the block,the block itself

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kinetic energy of the block is zero

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(C) Observer $B$ is standing on the block,which means observer $B$ is in a non-inertial frame of reference.In the frame of the block,the block itself is always at rest. Therefore,the velocity of the block with respect to observer $B$ is always zero.Since the velocity is zero,the kinetic energy of the block with respect to observer $B$ is also zero $(K.E. = \frac{1}{2} m v_{rel}^2 = 0)$.Thus,options $A$ and $B$ are incorrect because they describe motion relative to the ground,not relative to the block. Option $C$ is correct because the block is stationary in the frame of reference of observer $B$.

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