(B) The angular momentum vector $\vec{L}$ of a rotating body is given by $\vec{L} = I\vec{\omega}$.For a rod rotating about an axis passing through on

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

down at $20^o$ to the horizontal

(B) The angular momentum vector $\vec{L}$ of a rotating body is given by $\vec{L} = I\vec{\omega}$.For a rod rotating about an axis passing through one end at an angle $\theta = 20^o$ with the vertical,the angular momentum vector $\vec{L}$ does not lie along the axis of rotation.Instead,it is perpendicular to the rod. Since the rod makes an angle of $20^o$ with the vertical,the angle it makes with the horizontal is $90^o - 20^o = 70^o$.The angular momentum vector $\vec{L}$ is perpendicular to the rod,so it makes an angle of $20^o$ with the horizontal plane.As the rod rotates,the angular momentum vector $\vec{L}$ points downwards at an angle of $20^o$ to the horizontal,as shown in the diagram.

Class 11 Physics System of Particles and Rotational Motion Mix Example - System of Particles and Rotational Motion

Difficult

$A$ uniform rod is fixed to a rotating turntable so that its lower end is on the axis of the turntable and it makes an angle of $20^o$ to the vertical. (The rod is thus rotating with uniform angular velocity about a vertical axis passing through one end.) If the turntable is rotating clockwise as seen from above,what is the direction of the rod's angular momentum vector (calculated about its lower end)?

A
vertically downwards
B
down at $20^o$ to the horizontal
C
up at $20^o$ to the horizontal
D
vertically upwards

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

System of Particles and Rotational Motion

Subtopic

Mix Example - System of Particles and Rotational Motion

$A$ uniform rod $AB$ of mass $m$ and length $\ell$ is at rest on a smooth horizontal surface. An impulse $P$ is applied to the end $B$ perpendicular to the rod. The time taken by the rod to turn through a right angle is

MediumMHT CET 2020

View Solution

In the figure shown,a ring $A$ is initially rolling without sliding with a velocity $v$ on the horizontal surface of the body $B$ (of the same mass as $A$). All surfaces are smooth. $B$ has no initial velocity. What will be the maximum height reached by $A$ on $B$?

Difficult

View Solution

$A$ block of mass $m = 1 \, kg$ slides with velocity $v = 6 \, m/s$ on a frictionless horizontal surface and collides with a uniform vertical rod and sticks to it as shown. The rod is pivoted about $O$ and swings as a result of the collision,making an angle $\theta$ before momentarily coming to rest. If the rod has mass $M = 2 \, kg$ and length $l = 1 \, m$,the value of $\theta$ is approximately (Take $g = 10 \, m/s^2$) (in $^{\circ}$)

DifficultJEE MAIN 2020

View Solution

$A$,$B$,and $C$ are a disc,a solid sphere,and a spherical shell respectively,with the same radii $(R)$ and masses $(M)$. These bodies are placed as shown in the figure. The moment of inertia of the given system about the axis $PQ$ is $\frac{x}{15} I$,where $I$ is the moment of inertia of the disc about its diameter. The value of $x$ is . . . . . . .

DifficultJEE MAIN 2025

View Solution

$A$ uniform rod $AB$ of mass $2 \ kg$ and length $30 \ cm$ is at rest on a smooth horizontal surface. An impulse of force $0.2 \ Ns$ is applied to end $B$. The time taken by the rod to turn through a right angle will be $\frac{\pi}{X} \ s$,where $X = \text{ . . . . . . }$.

DifficultJEE MAIN 2024

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

$A$ uniform rod $AB$ of mass $m$ and length $\ell$ is at rest on a smooth horizontal surface. An impulse $P$ is applied to the end $B$ perpendicular to the rod. The time taken by the rod to turn through a right angle is

In the figure shown,a ring $A$ is initially rolling without sliding with a velocity $v$ on the horizontal surface of the body $B$ (of the same mass as $A$). All surfaces are smooth. $B$ has no initial velocity. What will be the maximum height reached by $A$ on $B$?

$A$ uniform rod $AB$ of mass $2 \ kg$ and length $30 \ cm$ is at rest on a smooth horizontal surface. An impulse of force $0.2 \ Ns$ is applied to end $B$. The time taken by the rod to turn through a right angle will be $\frac{\pi}{X} \ s$,where $X = \text{ . . . . . . }$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module