C_6H_6 xrightarrow[(ii),,Zn-Hg/HCl]{(i),,CH_3 | vedclass

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(D) Step $1$: Friedel-Crafts acylation of benzene $(C_6H_6)$ with acetyl chloride $(CH_3COCl)$ in the presence of $AlCl_3$ gives acetophenone $(C_6H_5

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$1-$Phenylethanol

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(D) Step $1$: Friedel-Crafts acylation of benzene $(C_6H_6)$ with acetyl chloride $(CH_3COCl)$ in the presence of $AlCl_3$ gives acetophenone $(C_6H_5COCH_3)$.Step $2$: Clemmensen reduction of acetophenone using $Zn-Hg/HCl$ reduces the carbonyl group to a methylene group,yielding ethylbenzene $(C_6H_5CH_2CH_3)$.Step $3$: Reaction of ethylbenzene with $NBS$ ($N$-bromosuccinimide) leads to benzylic bromination,forming $1-$bromo$-1-$phenylethane $(C_6H_5CH(Br)CH_3)$.Step $4$: Hydrolysis of $1-$bromo$-1-$phenylethane with $H_2O/K_2CO_3$ (nucleophilic substitution) yields $1-$phenylethanol $(C_6H_5CH(OH)CH_3)$ as the major product.

$C_6H_6$ $\xrightarrow[(ii)\,\,Zn-Hg/HCl]{(i)\,\,CH_3COCl/AlCl_3}$ $(P)$ $\xrightarrow[(ii)\,\,H_2O/K_2CO_3]{(i)\,\,NBS}$ $(Q)$
Major product $(Q)$ of the following sequence is:

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$C_6H_6$ $\xrightarrow[(ii)\,\,Zn-Hg/HCl]{(i)\,\,CH_3COCl/AlCl_3}$ $(P)$ $\xrightarrow[(ii)\,\,H_2O/K_2CO_3]{(i)\,\,NBS}$ $(Q)$Major product $(Q)$ of the following sequence is: