$1 \text{ mole}$ of $MnO_4^{2-}$ disproportionates into $MnO_4^-$ and $MnO_2$ in an acidic medium. Calculate the percentage by mass of $Mn$ converted to $MnO_4^-$ (Molar mass of $Mn = 55 \ g/mol$).

When $Cl_2$ gas reacts with hot and concentrated sodium hydroxide solution,the oxidation number of chlorine changes from

When $H_2S$ is passed through $Hg_2^{2+}$ solution,the products obtained are:

Assign $A, B, C, D$ from the given type of reaction.
$Na_2S + H_2SO_4$ $(Conc.)$ $\longrightarrow S\downarrow + SO_2 + Na_2SO_4$

For the given reaction $Cl_2 + OH^{-} \to ClO^{-} + Cl^{-}$,select the correct sequence of $T$ (True) and $F$ (False) for the following statements:
$(1)$ The given reaction occurs in a basic medium.
$(2)$ $Cl_2$ undergoes both oxidation and reduction.
$(3)$ The reaction is a disproportionation reaction.
$(4)$ The oxidation state of $Cl$ in $ClO^{-}$ is $+1$.

In acidic solution, $MnO_4^{2-}$ converts into . . . . . . .