$Me_3B$,$BH_3$,and $BF_3$ are three Lewis acids. Which one of the following is the correct sequence of these acids in order of their increasing acid strength?

  • A
    $Me_3B < BH_3 < BF_3$
  • B
    $Me_3B < BF_3 < BH_3$
  • C
    $BF_3 < Me_3B < BH_3$
  • D
    $BF_3 < BH_3 < Me_3B$

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Which of the following statements is true with respect to $H_2O$,$NH_3$ and $CH_4$?
$A.$ The central atoms of all the molecules are $sp^3$ hybridized.
$B.$ The $H-O-H$,$H-N-H$ and $H-C-H$ angles in the above molecules are $104.5^{\circ}$,$107.5^{\circ}$ and $109.5^{\circ}$ respectively.
$C.$ The increasing order of dipole moment is $CH_4 < NH_3 < H_2O$.
$D.$ Both $H_2O$ and $NH_3$ are Lewis acids and $CH_4$ is a Lewis base.
$E.$ $A$ solution of $NH_3$ in $H_2O$ is basic. In this solution,$NH_3$ and $H_2O$ act as a Lowry-Bronsted base and acid respectively.
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