(CH_3)_3C-CH(O)CH_2 + CH_3SNa xrightarrow{C_2 | vedclass

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(A) The reaction involves the nucleophilic ring opening of an epoxide ($2$-tert-butyl-oxirane) by the methanethiolate ion $(CH_3S^-)$.In a protic solv

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$CH_3S-CH_2-CH(OH)-C(CH_3)_3$

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(A) The reaction involves the nucleophilic ring opening of an epoxide ($2$-tert-butyl-oxirane) by the methanethiolate ion $(CH_3S^-)$.In a protic solvent like $C_2H_5OH$,the $S_N2$ mechanism dominates.The nucleophile $CH_3S^-$ attacks the less sterically hindered carbon atom of the epoxide ring,which is the $CH_2$ group.The epoxide ring opens,and the resulting alkoxide ion is protonated by the solvent to yield the final product,$CH_3S-CH_2-CH(OH)-C(CH_3)_3$.

$(CH_3)_3C-CH(O)CH_2 + CH_3SNa \xrightarrow{C_2H_5OH} ?$
The product formed is:

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$(CH_3)_3C-CH(O)CH_2 + CH_3SNa \xrightarrow{C_2H_5OH} ?$The product formed is: