CH_3-C(CH_3)=CH-CH_2-CH_2-Cl xrightarrow[CaCO | vedclass

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(D) The reaction proceeds via a homoallylic carbocation intermediate.The ionization of the $C-Cl$ bond in $CH_3-C(CH_3)=CH-CH_2-CH_2-Cl$ initially for

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$2-$cyclopropylpropan$-2-$ol

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(D) The reaction proceeds via a homoallylic carbocation intermediate.The ionization of the $C-Cl$ bond in $CH_3-C(CH_3)=CH-CH_2-CH_2-Cl$ initially forms a primary carbocation,which is stabilized by the neighboring $\pi$ bond (homoallylic participation).This leads to the formation of a more stable tertiary cyclopropylmethyl cation ($2$-cyclopropylpropan-$2$-yl cation).Nucleophilic attack by $H_2O$ on this tertiary carbocation yields $2$-cyclopropylpropan-$2$-ol as the major product.

$CH_3-C(CH_3)=CH-CH_2-CH_2-Cl \xrightarrow[CaCO_3]{H_2O} (X)$
The major product $(X)$ of the above reaction is:

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$CH_3-C(CH_3)=CH-CH_2-CH_2-Cl \xrightarrow[CaCO_3]{H_2O} (X)$The major product $(X)$ of the above reaction is: