$I$. $FeCr_2O_4 + NaOH + \text{air} \rightarrow Na_2CrO_4 + Fe_2O_3$
$II$. $Na_2CrO_4 + H_2SO_4 \rightarrow Na_2Cr_2O_7$
$Na_2CrO_4$ and $Fe_2O_3$ are separated by:

  • A
    dissolving in conc. $H_2SO_4$
  • B
    dissolving in $NH_3$
  • C
    dissolving in $H_2O$
  • D
    dissolving in dil. $HCl$

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