Consider the following reactions at 1000,^{ci | vedclass

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(B) To determine if $C$ can reduce $ZnO$,we consider the reaction: $ZnO_{(s)} + C_{(s)} \rightarrow Zn_{(s)} + CO_{(g)}$.This reaction is the differen

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$ZnO$ can be reduced to $Zn$ by $C$

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(B) To determine if $C$ can reduce $ZnO$,we consider the reaction: $ZnO_{(s)} + C_{(s)} \rightarrow Zn_{(s)} + CO_{(g)}$.This reaction is the difference between reaction $(II)$ and reaction $(I)$:$\Delta G^o_{reaction} = \Delta G^o_{(II)} - \Delta G^o_{(I)}$$\Delta G^o_{reaction} = -460\,kJ\,mol^{-1} - (-360\,kJ\,mol^{-1}) = -100\,kJ\,mol^{-1}$.Since the overall $\Delta G^o$ is negative,the reaction is spontaneous at $1000\,^{\circ}C$.Therefore,$ZnO$ can be reduced to $Zn$ by $C$.

Consider the following reactions at $1000\,^{\circ}C$:
$(I)$ $Zn_{(s)} + 1/2 O_{2(g)} \xrightarrow{\Delta} ZnO_{(s)};$ $\Delta G^o = -360\,kJ\,mol^{-1}$
$(II)$ $C_{(s)} + 1/2 O_{2(g)} \xrightarrow{\Delta} CO_{(g)};$ $\Delta G^o = -460\,kJ\,mol^{-1}$
Choose the correct statement at $1000\,^{\circ}C$.

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Consider the following reactions at $1000\,^{\circ}C$:$(I)$ $Zn_{(s)} + 1/2 O_{2(g)} \xrightarrow{\Delta} ZnO_{(s)};$ $\Delta G^o = -360\,kJ\,mol^{-1}$$(II)$ $C_{(s)} + 1/2 O_{2(g)} \xrightarrow{\Delta} CO_{(g)};$ $\Delta G^o = -460\,kJ\,mol^{-1}$Choose the correct statement at $1000\,^{\circ}C$.