$R-NH_2 \to R-NH-CH_3$ (major product). The correct sequence of reagents is:

  • A
    $CH_3-CO-Cl$
  • B
    $CH_3I$ (excess)
  • C
    $CHCl_3 + KOH$ followed by $LiAlH_4$
  • D
    $NaNO_2 + HCl$ $(0-5^\circ C)$; $(CH_3)_2NH$

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Similar Questions

Starting from propanoic acid,the following reactions were carried out: $CH_3-CH_2-COOH$ $\xrightarrow{SOCl_2} X$ $\xrightarrow{NH_3} Y$ $\xrightarrow{Br_2 + KOH} Z$. What is the compound $Z$?

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Identify $X$ and $Y$ in the following reactions:
$Nitrobenzene \xrightarrow{Zn/NH_4Cl} X$
$Nitrobenzene \xrightarrow{Zn + KOH/C_2H_5OH} Y$

Aniline $\xrightarrow[{{0^{\circ}}C - {5^{\circ}}C}]{{NaNO_2/HCl}}A$ $\xrightarrow{{Ph-N(CH_3)_2}}B$
What is $B$?

The descending order of basicity of the following amines is $:$
$(A)$ Aniline
$(B)$ $p$-Methoxyaniline
$(C)$ $p$-Nitroaniline
$(D)$ Methylamine
$(E)$ Dimethylamine
Choose the correct answer from the options given below $:$

Complete reduction of $benzene-diazonium$ chloride with $Zn/HCl$ gives:

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