$A$ $2\,kg$ copper block is heated to $500^\circ C$ and then it is placed on a large block of ice at $0^\circ C$. If the specific heat capacity of copper is $400\, J/kg/ ^\circ C$ and latent heat of fusion of water is $3.5 \times 10^5\, J/kg$,the amount of ice that can melt is:

  • A
    $7/8\, kg$
  • B
    $7/5\, kg$
  • C
    $8/7\, kg$
  • D
    $5/7\, kg$

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Steam of mass $60 \ g$ at a temperature $100^{\circ} C$ is mixed with water of mass $360 \ g$ at a temperature $40^{\circ} C$. The ratio of the masses of steam and water in equilibrium is (Latent heat of steam is $540 \ cal \ g^{-1}$ and specific heat capacity of water is $1 \ cal \ g^{-1} {}^{\circ} C^{-1}$)

An unknown metal of mass $192 \, g$ heated to a temperature of $100 \, ^oC$ was immersed into a brass calorimeter of mass $128 \, g$ containing $240 \, g$ of water at a temperature of $8.4 \, ^oC$. Calculate the specific heat of the unknown metal if the water temperature stabilizes at $21.5 \, ^oC$. (Specific heat of brass is $394 \, J \, kg^{-1} \, K^{-1}$, specific heat of water is $4186 \, J \, kg^{-1} \, K^{-1}$) ......... $J \, kg^{-1} \, K^{-1}$

$A$ glass beaker contains $200 \,g$ of carbonated water initially at $20^{\circ} C$. How much ice should be added to obtain the final temperature of $0^{\circ} C$ with all ice melted, if the initial temperature of ice is $-10^{\circ} C$ (in $\,g$)? Neglect the heat capacity of the glass.
[Take, $C_{\text{water}} = 4190 \,J/kg^{\circ} C$, $C_{\text{ice}} = 2100 \,J/kg^{\circ} C$, $L_F = 3.34 \times 10^5 \,J/kg$]

Some steam at $100^o \, C$ is passed into $1.1 \, kg$ of water contained in a calorimeter of water equivalent $0.02 \, kg$ at $15^o C$ so that the temperature of the calorimeter and its contents rises to $80^o \, C$. What is the mass of steam condensing (in $kg$)?

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$A$ vessel contains $110\,g$ of water. The heat capacity of the vessel is equivalent to $10\,g$ of water. The initial temperature of the water in the vessel is $10\,^{\circ}C$. If $220\,g$ of hot water at $70\,^{\circ}C$ is poured into the vessel,the final temperature,neglecting radiation loss,will be nearly equal to ........ $^{\circ}C$.

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