A 120, g mass has a velocity vec v = 2hat i + | vedclass

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(D) The kinetic energy $(K.E.)$ of an object is given by the formula: $K.E. = \frac{1}{2} mv^2$.First,convert the mass from grams to kilograms: $m = 1

Vedclass · Accepted Answer

$1.74$

Vedclass · Answer

(D) The kinetic energy $(K.E.)$ of an object is given by the formula: $K.E. = \frac{1}{2} mv^2$.First,convert the mass from grams to kilograms: $m = 120\, g = 0.12\, kg$.Next,calculate the square of the velocity magnitude $(v^2)$ using the dot product of the velocity vector with itself: $v^2 = \vec{v} \cdot \vec{v} = (2\hat{i} + 5\hat{j}) \cdot (2\hat{i} + 5\hat{j}) = (2^2 + 5^2) = 4 + 25 = 29\, m^2/s^2$.Now,substitute these values into the kinetic energy formula:$K.E. = \frac{1}{2} 	imes 0.12\, kg 	imes 29\, m^2/s^2$$K.E. = 0.06 	imes 29 = 1.74\, J$.Therefore,the kinetic energy is $1.74\, J$.

$A$ $120\, g$ mass has a velocity $\vec v = 2\hat i + 5\hat j\, m/s$ at a certain instant. Its kinetic energy is .................. $J$.

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