(D) Given: Number of turns $N = 800$,Area $A = 0.05\; m^{2}$,Magnetic field $B = 5 \times 10^{-5}\; T$,Time interval $\Delta t = 0.1\; s$.Initial magn

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(D) Given: Number of turns $N = 800$,Area $A = 0.05\; m^{2}$,Magnetic field $B = 5 \times 10^{-5}\; T$,Time interval $\Delta t = 0.1\; s$.Initial magnetic flux $\phi_{1} = N B A \cos(0^{\circ}) = N B A$.Final magnetic flux $\phi_{2} = N B A \cos(90^{\circ}) = 0$.Induced $emf$ $e = -\frac{\Delta \phi}{\Delta t} = -\frac{\phi_{2} - \phi_{1}}{\Delta t} = \frac{N B A}{\Delta t}$.Substituting the values: $e = \frac{800 \times 5 \times 10^{-5} \times 0.05}{0.1}$.$e = \frac{800 \times 5 \times 10^{-5} \times 5 \times 10^{-2}}{10^{-1}} = 800 \times 5 \times 5 \times 10^{-7} \times 10^{1} = 20000 \times 10^{-6} = 0.02\; V$.

Class 12 Physics Electromagnetic Induction Motional EMI (Induced Parameter)

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$A$ $800$ turn coil of effective area $0.05\; m^{2}$ is kept perpendicular to a magnetic field $5 \times 10^{-5}\; T$. When the plane of the coil is rotated by $90^{\circ}$ around any of its coplanar axes in $0.1\; s$,the $emf$ induced in the coil will be.....$V$

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A
$2$
B
$0.2$
C
$2 \times 10^{-3}$
D
$0.02$

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Motional EMI (Induced Parameter)

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$A$ $800$ turn coil of effective area $0.05\; m^{2}$ is kept perpendicular to a magnetic field $5 \times 10^{-5}\; T$. When the plane of the coil is rotated by $90^{\circ}$ around any of its coplanar axes in $0.1\; s$,the $emf$ induced in the coil will be.....$V$

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$A$ constant force $F$ is applied to a conducting rod of length $l$ moving with constant speed $V$ on two parallel conducting rails connected at the ends by a resistance $R$ in a uniform magnetic field $B$,as shown. If the current flowing through the circuit is $I$,then:

$A$ conducting rod $PQ$ of length $L = 1.0\, m$ is moving with a uniform speed $v = 2\, m/s$ in a uniform magnetic field $B = 4.0\, T$ directed into the paper. $A$ capacitor of capacity $C = 10\,\mu F$ is connected as shown in the figure. Then

$A$ thin wire of length $2 \ m$ is perpendicular to the $xy$-plane. It moves with a velocity $v = (2\hat{i} + 3\hat{j} + \hat{k}) \ m/s$ in a magnetic field $B = (\hat{i} + 2\hat{j}) \ Wb/m^2$. What is the induced potential difference (emf) across the ends of the wire?

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