A jet plane is travelling towards west at a s | vedclass

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(A) Speed of the jet plane,$v = 1800\; km/h = 500\; m/s$.Wing span of the jet plane,$l = 25\; m$.Earth's magnetic field strength,$B = 5.0 	imes 10^{-

Vedclass · Accepted Answer

$3.125$

Vedclass · Answer

(A) Speed of the jet plane,$v = 1800\; km/h = 500\; m/s$.Wing span of the jet plane,$l = 25\; m$.Earth's magnetic field strength,$B = 5.0 	imes 10^{-4}\; T$.Angle of dip,$\delta = 30^{\circ}$.The vertical component of the Earth's magnetic field,$B_v = B \sin \delta$.$B_v = 5 	imes 10^{-4} 	imes \sin 30^{\circ} = 5 	imes 10^{-4} 	imes 0.5 = 2.5 	imes 10^{-4}\; T$.The induced electromotive force (voltage difference) between the ends of the wing is given by $e = B_v 	imes l 	imes v$.$e = 2.5 	imes 10^{-4} 	imes 25 	imes 500$.$e = 3.125\; V$.Thus,the voltage difference developed between the ends of the wings is $3.125\; V$.

$A$ jet plane is travelling towards west at a speed of $1800\; km/h$. What is the voltage difference developed between the ends of the wing having a span of $25\; m$,if the Earth's magnetic field at the location has a magnitude of $5 \times 10^{-4}\; T$ and the dip angle is $30^{\circ}$ (in $; V$)?

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