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(B) Let the length of the ladder be the hypotenuse $h = 4 \,m$.Let the height reached on the wall be the perpendicular $p = 3.2 \,m$.Let the distance

Vedclass · Accepted Answer

$2.4$

Vedclass · Answer

(B) Let the length of the ladder be the hypotenuse $h = 4 \,m$.Let the height reached on the wall be the perpendicular $p = 3.2 \,m$.Let the distance between the base of the wall and the lower end of the ladder be the base $b$.According to the Pythagorean theorem,$h^2 = p^2 + b^2$.Substituting the values: $4^2 = (3.2)^2 + b^2$.$16 = 10.24 + b^2$.$b^2 = 16 - 10.24 = 5.76$.$b = \sqrt{5.76} = 2.4 \,m$.

$A$ $4 \,m$ long ladder leans on a wall to reach a height of $3.2 \,m$ on the wall. Find the distance in $m$ between the lower end of the ladder and the base of the wall.

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