In rectangle $ABCD$,$AC = 25$ and $CD = 7$. Then,the perimeter of the rectangle is........

  • A
    $64$
  • B
    $62$
  • C
    $49$
  • D
    $56$

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In rectangle $HIJK$,$HJ = 13$ and $HI = 5$. Then,the perimeter of rectangle $HIJK$ is.......

In $Fig.$,line segment $DF$ intersects the side $AC$ of a triangle $ABC$ at the point $E$ such that $E$ is the mid-point of $CA$ and $\angle AEF = \angle AFE$. Prove that
$\frac{BD}{CD} = \frac{BF}{CE}$

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