In rectangle HIJK,HJ = 13 and HI = 5. Then,th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In rectangle $HIJK$,$HJ$ is the diagonal and $HI$ is one of the sides.Let the sides be $HI = l = 5$ and $IJ = w$. The diagonal $HJ$ forms a right-

Vedclass · Accepted Answer

$34$

Vedclass · Answer

(A) In rectangle $HIJK$,$HJ$ is the diagonal and $HI$ is one of the sides.Let the sides be $HI = l = 5$ and $IJ = w$. The diagonal $HJ$ forms a right-angled triangle $	riangle HIJ$ with sides $HI$ and $IJ$.By the Pythagorean theorem,$HI^2 + IJ^2 = HJ^2$.$5^2 + IJ^2 = 13^2$.$25 + IJ^2 = 169$.$IJ^2 = 169 - 25 = 144$.$IJ = \sqrt{144} = 12$.Now,the perimeter of the rectangle is given by $P = 2(l + w)$.$P = 2(5 + 12) = 2(17) = 34$.

In rectangle $HIJK$,$HJ = 13$ and $HI = 5$. Then,the perimeter of rectangle $HIJK$ is.......

Similar Questions

Out of the following triplets,$\ldots \ldots \ldots \ldots$ is not a Pythagorean triplet.

In $\Delta ABC$,$m \angle B = 90^{\circ}$ and $\overline{BM}$ is a median. If $AB = 20$ and $BC = 21$,find $BM$. (in $.5$)

If $S$ is a point on side $PQ$ of a $\triangle PQR$ such that $PS = QS = RS$,then

In $\Delta ABC$,$A-M-B$,$A-N-C$ and $\overline{MN} \parallel \overline{BC}$. If $\frac{AM}{MB} = \frac{2}{3}$ and $AC = 25$,find $NC$.

In $\Delta PQR$,$m \angle Q = 90^{\circ}$ and $\overline{QD}$ is an altitude to the hypotenuse $PR$. If $QD = 15$ and $PR = 34$,find $PQ$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module